F(4)-5=4n^2+3n

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Solution for F(4)-5=4n^2+3n equation: 



(4)-5=4F^2+3F

We move all terms to the left:

(4)-5-(4F^2+3F)=0

We add all the numbers together, and all the variables

-(4F^2+3F)-1=0

We get rid of parentheses

-4F^2-3F-1=0

a = -4; b = -3; c = -1;
Δ = b2-4ac
Δ = -32-4·(-4)·(-1)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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